Abstract
The problem of avoiding a single pattern or a pair of patterns of length four by permutations has been well studied. Less is known about the avoidance of three 4-letter patterns. In this paper, we show that the number of members of Sn avoiding any one of twelve triples of 4-letter patterns is given by sequence A129775 in OEIS, which is known to count maximally clustered permutations. Numerical evidence confirms that there are no other (non-trivial) triples of 4-letter patterns giving rise to this sequence and hence one obtains the largest (4, 4, 4)-Wilf-equivalence class for permutations. We make use of a variety of methods in proving our result, including recurrences, the kernel method, direct counting, and bijections.
Original language | English |
---|---|
Pages (from-to) | 41-74 |
Number of pages | 34 |
Journal | Annales Mathematicae et Informaticae |
Volume | 47 |
State | Published - 2017 |
Bibliographical note
Publisher Copyright:© 2017, Eszterhazy Karoly College. All rights reserved.
Keywords
- Kernel method
- Maximally clustered permutations
- Pattern avoidance
- Wilf-equivalence
ASJC Scopus subject areas
- General Computer Science
- General Mathematics