Abstract
We provide a proof of a geometric inequality relating the cube of the distances of an arbitrary point from the vertices of a triangle to the cube of the inradius of the triangle. Comparable versions of the inequality involving second and fourth powers may be obtained by modifying our arguments.
| Original language | English |
|---|---|
| Pages (from-to) | 175–181 |
| Journal | Forum Geometricorum |
| Volume | 11 |
| State | Published - 1 Jan 2011 |